前言
Python 3.11
pyparsing 3.1.2
案例
# encoding: utf-8
# author: qbit
# date: 2024-04-23
# summary: 化簡括號冗餘的與或非邏輯表達式
import pyparsing as pp
line = '(((owner=111 AND doc_type=222))) OR author=333 OR organ=444 AND ((NOT pub_year>555))'
operator = (
pp.Literal(r'=') |
pp.Literal(r'>')
)
field = pp.Word(pp.alphanums + '_')
value = pp.Word(pp.alphanums)
exprGroup: pp.Group = pp.Group(field("field") + operator("operator") + value("value"))
logicAND = pp.Word('AND')('logic')
logicOR = pp.Word('OR')('logic')
logicNOT = pp.Word('NOT')('logic')
exprForward = pp.infixNotation(
exprGroup("Expr"),
[
(logicAND, 2, pp.opAssoc.LEFT, ), # 第二個參數為操作數的個數,並不是結合優先級
(logicOR, 2, pp.opAssoc.LEFT, ),
(logicNOT, 1, pp.opAssoc.RIGHT, ),
]
).setResultsName("Result", True)
result: pp.results.ParseResults = exprForward.parseString(line, parseAll=True)
def list2qs(lst):
if (len(lst) == 1) and isinstance(lst[0], list): # 列表中只有一個列表元素
return list2qs(lst[0])
if lst[0] == 'NOT':
return f"(NOT {list2qs(lst[1])})"
if lst[1] == 'AND':
return ' AND '.join( [list2qs(x) for x in lst[0::2]]) # 步長為2取數據
if lst[1] == 'OR':
return ' OR '.join( [list2qs(x) for x in lst[0::2]]) # 步長為2取數據
match lst[1]:
case r'=':
return f"{lst[0]}={lst[2]}"
case r'>':
return f"{lst[0]}>{lst[2]}"
case _:
pass
qs = list2qs(result.as_list())
print(f"冗餘表達式: {line}")
print(f"簡化表達式: {qs}")
冗餘表達式: (((owner=111 AND doc_type=222))) OR author=333 OR organ=444 AND ((NOT pub_year>555))
簡化表達式: owner=111 AND doc_type=222 OR author=333 OR organ=444 AND (NOT pub_year>555)
相關資料
庫
- https://pypi.org/project/pyparsing/
- https://pypi.org/project/boolean-parser
- https://pypi.org/project/parsimonious/
- https://pypi.org/project/sympy/
文章
- PyParsing 官方文檔:https://pyparsing-docs.readthedocs.io/en/latest/
- pyparsing 學習(博客園)
- 取代正則-使用pyparsing來定製自己的解析器(知乎)
- Pyparsing快速構建解釋器 | 實戰搜索查詢語法(知乎)
- parsing logical expression with pyparsing
- Pyparsing實戰(知乎)
- 用 pyparsing 3.x 將與或非邏輯表達式轉換為Elasticsearch查詢語句
本文出自 qbit snap